path: root/Test/D06subscript.ztst

# Test parameter subscripting.

%prep

  s='Twinkle, twinkle, little *, [how] I [wonder] what?  You are!'
  a=('1' ']'  '?' '\2'  '\]' '\?'  '\\3' '\\]'  '\\?' '\\\4'  '\\\]' '\\\?')
  typeset -g -A A
  A=($a)

%test

  x=','
  print $s[(i)winkle] $s[(I)winkle]
  print ${s[(i)You are]} $#s
  print ${s[(r)$x,(R)$x]}
0:Scalar pattern subscripts without wildcards
>2 11
>53 60
>, twinkle, little *,

  x='*'
  print $s[(i)*] $s[(i)\*] $s[(i)$x*] $s[(i)${(q)x}*] $s[(I)$x\*]
  print $s[(r)?,(R)\?] $s[(r)\?,(R)?]
  print $s[(r)\*,(R)*]
  print $s[(r)\],(R)\[]
0:Scalar pattern subscripts with wildcards
>1 26 1 26 26
>Twinkle, twinkle, little *, [how] I [wonder] what? ?  You are!
>*, [how] I [wonder] what?  You are!
>] I [

  print $s[(i)x] : $s[(I)x]
  print $s[(r)x] : $s[(R)x]
0:Scalar pattern subscripts that do not match
>61 : 0
>:

  print -R $s[$s[(i)\[]] $s[(i)$s[(r)\*]] $s[(i)${(q)s[(r)\]]}]
0:Scalar subscripting using a pattern subscript to get the index
>[ 1 33

  print -R $a[(r)?] $a[(R)?]
  print $a[(n:2:i)?] $a[(n:2:I)?]
  print $a[(i)\?] $a[(I)\?]
  print $a[(i)*] $a[(i)\*]
0:Array pattern subscripts
>1 ?
>2 2
>3 3
>1 13

  # It'd be nice to do some of the following with (r), but we run into
  # limitations of the ztst script parsing of backslashes in the output.
  print -R $a[(i)\\\\?] $a[(i)\\\\\?]
  print -R $a[(i)\\\\\\\\?] $a[(i)\\\\\\\\\?]
  print -R ${a[(i)\\\\\\\\?]} ${a[(i)\\\\\\\\\?]}
  print -R "$a[(i)\\\\\\\\?] $a[(i)\\\\\\\\\?]"
  print -R $a[(i)\]] $a[(i)\\\\\]] $a[(i)\\\\\\\\\]] $a[(i)\\\\\\\\\\\\\]]
  print -R $a[(i)${(q)a[5]}] $a[(i)${(q)a[8]}] $a[(i)${(q)a[11]}]
  print -R $a[(i)${a[3]}] $a[(i)${a[6]}] $a[(i)${a[9]}] $a[(i)${a[12]}]
0:Array pattern subscripts with multiple backslashes
>4 6
>7 9
>7 9
>7 9
>2 5 8 11
>5 8 11
>1 3 4 6

  print -R $A[1] $A[?] $A[\\\\3] $A[\\\]]
  print -R $A[$a[11]]
  print -R $A[${(q)a[5]}]
0:Associative array lookup (direct subscripting)
>] \2 \\] \?
>\\\?
>\\\?

  # The (o) is necessary here for predictable output ordering
  print -R $A[(I)\?] ${(o)A[(I)?]}
  print -R $A[(i)\\\\\\\\3]
  print -R $A[(I)\\\\\\\\\?] ${(o)A[(I)\\\\\\\\?]}
0:Associative array lookup (pattern subscripting)
>? 1 ?
>\\3
>\\? \\3 \\?

  print -R $A[(R)\?] : ${(o)A[(R)?]}
  print -R $A[(R)\\\\\?] ${(o)A[(R)\\\\?]} ${(o)A[(R)\\\\\?]}
  print -R ${(o)A[(R)\\\\\\\\\]]}
0:Associative array lookup (reverse subscripting)
>: ]
>\? \2 \? \?
>\\]

  eval 'A[*]=star'
1:Illegal associative array assignment
?(eval):1: A: attempt to set slice of associative array

  x='*'
  A[$x]=xstar
  A[${(q)x}]=qxstar
  print -R ${(k)A[(r)xstar]} $A[$x]
  print -R ${(k)A[(r)qxstar]} $A[${(q)x}]
  A[(e)*]=star
  A[\*]=backstar
  print -R ${(k)A[(r)star]} $A[(e)*]
  print -R ${(k)A[(r)backstar]} $A[\*]
0:Associative array assignment
>* xstar
>\* qxstar
>* star
>\* backstar

  o='['
  c=']'
  A[\]]=cbrack
  A[\[]=obrack
  A[\\\[]=backobrack
  A[\\\]]=backcbrack
  print -R $A[$o] $A[$c] $A[\[] $A[\]] $A[\\\[] $A[\\\]]
  print -R $A[(i)\[] $A[(i)\]] $A[(i)\\\\\[] $A[(i)\\\\\]]
0:Associative array keys with open and close brackets
>obrack cbrack obrack cbrack backobrack backcbrack
>[ ] \[ \]

  print -R $A[$o] $A[$s[(r)\[]]
  print -R $A[(r)$c] $A[(r)$s[(r)\]]]
  print -R $A[$A[(i)\\\\\]]]
0:Associative array lookup using a pattern subscript to get the key
>obrack obrack
>] ]
>backcbrack

  print -R ${A[${A[(r)\\\\\\\\\]]}]::=zounds}
  print -R ${A[${A[(r)\\\\\\\\\]]}]}
  print -R $A[\\\\\]]
0:Associative array substitution-assignment with reverse pattern subscript key
>zounds
>zounds
>zounds

  print -R ${(o)A[(K)\]]}
  print -R ${(o)A[(K)\\\]]}
0:Associative array keys interpreted as patterns
>\2 backcbrack cbrack star
>\\\4 \\\? star zounds

# It doesn't matter which element we get, since we never guarantee
# ordering of an associative array.  So just test the number of matches.
  array=(${(o)A[(k)\]]})
  print ${#array}
  array=(${(o)A[(k)\\\]]})
  print ${#array}
0:Associative array keys interpreted as patterns, single match
>1
>1

  typeset -g "A[one\"two\"three\"quotes]"=QQQ
  typeset -g 'A[one\"two\"three\"quotes]'=qqq
  print -R "$A[one\"two\"three\"quotes]"
  print -R $A[one\"two\"three\"quotes]
  A[one"two"three"four"quotes]=QqQq
  print -R $A[one"two"three"four"quotes]
  print -R $A[$A[(i)one\"two\"three\"quotes]]
  print -R "$A[$A[(i)one\"two\"three\"quotes]]"
0:Associative array keys with double quotes
>QQQ
>qqq
>QqQq
>qqq
>QQQ

  print ${x::=$A[$A[(i)one\"two\"three\"quotes]]}
  print $x
  print ${x::="$A[$A[(i)one\"two\"three\"quotes]]"}
  print $x
0:More keys with double quotes, used in assignment-expansion
>qqq
>qqq
>QQQ
>QQQ

  qqq=lower
  QQQ=upper
  print ${(P)A[one\"two\"three\"quotes]}
  print "${(P)A[$A[(i)one\"two\"three\"quotes]]}"
0:Keys with double quotes and the (P) expansion flag
>lower
>upper

  typeset -ga empty
  echo X${${empty##*}[-1]}X
0:Negative index applied to substitution result from empty array
>XX

  print $empty[(i)] $empty[(I)]
0:(i) returns 1 for empty array, (I) returns 0.
>1 0

  array=(one two three four)
  print X$array[0]X
0:Element zero is empty if KSH_ZERO_SUBSCRIPT is off.
>XX

  array[0]=fumble
1:Can't set element zero if KSH_ZERO_SUBSCRIPT is off.
?(eval):1: array: assignment to invalid subscript range

  print X$array[(R)notfound]X
0:(R) returns empty if not found if KSH_ZERO_SUBSCRIPT is off.
>XX

  setopt KSH_ZERO_SUBSCRIPT
  print X$array[0]X
0:Element zero is element one if KSH_ZERO_SUBSCRIPT is on.
>XoneX

  array[0]=fimble
  print $array
0:Can set element zero if KSH_ZERO_SUBSCRIPT is on.
>fimble two three four

  print X$array[(R)notfound]X
0:(R) yuckily returns the first element on failure with KSH_ZERO_SUBSCRIPT
>XfimbleX

  unsetopt KSH_ZERO_SUBSCRIPT
  array[(R)notfound,(r)notfound]=(help help here come the seventies retreads)
  print $array
0:[(R)notfound,(r)notfound] replaces the whole array
>help help here come the seventies retreads

  string="Why, if it isn't Officer Dibble"
  print "[${string[0]}][${string[1]}][${string[0,3]}]"
0:String subscripts with KSH_ZERO_SUBSCRIPT unset
>[][W][Why]

  setopt KSH_ZERO_SUBSCRIPT
  print "[${string[0]}][${string[1]}][${string[0,3]}]"
0:String subscripts with KSH_ZERO_SUBSCRIPT set
>[W][W][Why]

  unsetopt KSH_ZERO_SUBSCRIPT
  string[0,3]="Goodness"
  print $string
0:Assignment to chunk of string ignores element 0
>Goodness, if it isn't Officer Dibble

  string[0]=!
1:Can't set only element zero of string
?(eval):1: string: assignment to invalid subscript range

  typeset -A assoc=(leader topcat officer dibble sidekick choochoo)
  alias myind='echo leader' myletter='echo 1' myletter2='echo 4'
  print ${assoc[$(myind)]}
  print $assoc[$(myind)]
  print ${assoc[$(myind)][$(myletter)]}${assoc[$(myind)][$(myletter2)]}
  assoc[$(myind)]='of the gang'
  print ${assoc[$(myind)]}
  print $assoc[$(myind)]
  print $assoc[leader]
0: Parsing subscript with non-trivial tokenisation
>topcat
>topcat
>tc
>of the gang
>of the gang
>of the gang

 string='abcde'
 twoarg() { return $(( $2 - $1 )) }
 functions -M twoarg
 print ${string[1,twoarg(1,4)]}
0:Commas inside parentheses do not confuse subscripts
>abc

  string='foobarbaz foob?rbaz foob?rbaz'
  print $string[(i)b?r] $string[(I)b?r]
  print $string[(r)b?r] $string[(R)b?r]
  print $string[(r)b?r,(R)b?r]
  print $string[(ei)b?r] $string[(eI)b?r]
  print $string[(er)b?r] $string[(eR)b?r]
  print $string[(er)b?r,(eR)b?r]
0:Pattern handling with scalars
F:Regression test for workers/42297
>4 24
>b b
>barbaz foob?rbaz foob?r
>14 24
>b b
>b?rbaz foob?r