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+# Test parameter subscripting.
+
+%prep
+
+  s='Twinkle, twinkle, little *, [how] I [wonder] what?  You are!'
+  a=('1' ']'  '?' '\2'  '\]' '\?'  '\\3' '\\]'  '\\?' '\\\4'  '\\\]' '\\\?')
+  typeset -g -A A
+  A=($a)
+
+%test
+
+  x=','
+  print $s[(i)winkle] $s[(I)winkle]
+  print ${s[(i)You are]} $#s
+  print ${s[(r)$x,(R)$x]}
+0:Scalar pattern subscripts without wildcards
+>2 11
+>53 60
+>, twinkle, little *,
+
+  x='*'
+  print $s[(i)*] $s[(i)\*] $s[(i)$x*] $s[(i)${(q)x}*] $s[(I)$x\*]
+  print $s[(r)?,(R)\?] $s[(r)\?,(R)?]
+  print $s[(r)\*,(R)*]
+  print $s[(r)\],(R)\[]
+0:Scalar pattern subscripts with wildcards
+>1 26 1 26 26
+>Twinkle, twinkle, little *, [how] I [wonder] what? ?  You are!
+>*, [how] I [wonder] what?  You are!
+>] I [
+
+  # $s[(R)x] actually is $s[0], but zsh treats 0 as 1 for subscripting.
+  print $s[(i)x] : $s[(I)x]
+  print $s[(r)x] : $s[(R)x]
+0:Scalar pattern subscripts that do not match
+>61 : 0
+>: T
+
+  print -R $s[$s[(i)\[]] $s[(i)$s[(r)\*]] $s[(i)${(q)s[(r)\]]}]
+0:Scalar subscripting using a pattern subscript to get the index
+>[ 1 33
+
+  print -R $a[(r)?] $a[(R)?]
+  print $a[(n:2:i)?] $a[(n:2:I)?]
+  print $a[(i)\?] $a[(I)\?]
+  print $a[(i)*] $a[(i)\*]
+0:Array pattern subscripts
+>1 ?
+>2 2
+>3 3
+>1 13
+
+  # It'd be nice to do some of the following with (r), but we run into
+  # limitations of the ztst script parsing of backslashes in the output.
+  print -R $a[(i)\\\\?] $a[(i)\\\\\?]
+  print -R $a[(i)\\\\\\\\?] $a[(i)\\\\\\\\\?]
+  print -R ${a[(i)\\\\\\\\?]} ${a[(i)\\\\\\\\\?]}
+  print -R "$a[(i)\\\\\\\\?] $a[(i)\\\\\\\\\?]"
+  print -R $a[(i)\]] $a[(i)\\\\\]] $a[(i)\\\\\\\\\]] $a[(i)\\\\\\\\\\\\\]]
+  print -R $a[(i)${(q)a[5]}] $a[(i)${(q)a[8]}] $a[(i)${(q)a[11]}]
+  print -R $a[(i)${a[3]}] $a[(i)${a[6]}] $a[(i)${a[9]}] $a[(i)${a[12]}]
+0:Array pattern subscripts with multiple backslashes
+>4 6
+>7 9
+>7 9
+>7 9
+>2 5 8 11
+>5 8 11
+>1 3 4 6
+
+  print -R $A[1] $A[?] $A[\\\\3] $A[\\\]]
+  print -R $A[$a[11]]
+  print -R $A[${(q)a[5]}]
+0:Associative array lookup (direct subscripting)
+>] \2 \\] \?
+>\\\?
+>\\\?
+
+  # The (o) is necessary here for predictable output ordering
+  print -R $A[(I)\?] ${(o)A[(I)?]}
+  print -R $A[(i)\\\\\\\\3]
+  print -R $A[(I)\\\\\\\\\?] ${(o)A[(I)\\\\\\\\?]}
+0:Associative array lookup (pattern subscripting)
+>? 1 ?
+>\\3
+>\\? \\3 \\?
+
+  print -R $A[(R)\?] : ${(o)A[(R)?]}
+  print -R $A[(R)\\\\\?] ${(o)A[(R)\\\\?]} ${(o)A[(R)\\\\\?]}
+  print -R ${(o)A[(R)\\\\\\\\\]]}
+0:Associative array lookup (reverse subscripting)
+>: ]
+>\? \2 \? \?
+>\\]
+
+  x='*'
+  A[$x]=xstar
+  A[${(q)x}]=qxstar
+  print -R ${(k)A[(r)xstar]} $A[$x]
+  print -R ${(k)A[(r)qxstar]} $A[${(q)x}]
+  # A[*] is interpreted specially, assignment to it fails silently (oops)
+  A[*]=star
+  A[\*]=backstar
+  print -R ${(k)A[(r)star]} $A[$x]
+  print -R ${(k)A[(r)backstar]} $A[\*]
+0:Associative array assignment
+>* xstar
+>\* qxstar
+>xstar
+>\* backstar
+
+  o='['
+  c=']'
+  A[\]]=cbrack
+  A[\[]=obrack
+  A[\\\[]=backobrack
+  A[\\\]]=backcbrack
+  print -R $A[$o] $A[$c] $A[\[] $A[\]] $A[\\\[] $A[\\\]]
+  print -R $A[(i)\[] $A[(i)\]] $A[(i)\\\\\[] $A[(i)\\\\\]]
+0:Associative array keys with open and close brackets
+>obrack cbrack obrack cbrack backobrack backcbrack
+>[ ] \[ \]
+
+  print -R $A[$o] $A[$s[(r)\[]]
+  print -R $A[(r)$c] $A[(r)$s[(r)\]]]
+  print -R $A[$A[(i)\\\\\]]]
+0:Associative array lookup using a pattern subscript to get the key
+>obrack obrack
+>] ]
+>backcbrack