1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
|
/* rawmemchr -- find a byte within an unsized memory block.
Copyright (C) 2013-2018 Free Software Foundation, Inc.
This file is part of the GNU C Library.
The GNU C Library is free software; you can redistribute it and/or
modify it under the terms of the GNU Lesser General Public
License as published by the Free Software Foundation; either
version 2.1 of the License, or (at your option) any later version.
The GNU C Library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public
License along with the GNU C Library. If not, see
<http://www.gnu.org/licenses/>. */
#include <sysdep.h>
.syntax unified
.text
ENTRY (__rawmemchr)
@ r0 = start of string
@ r1 = character to match
@ returns a pointer to the match, which must be present.
ldrb r2, [r0] @ load first byte asap
@ To cater to long strings, we want to search through a few
@ characters until we reach an aligned pointer. To cater to
@ small strings, we don't want to start doing word operations
@ immediately. The compromise is a maximum of 16 bytes less
@ whatever is required to end with an aligned pointer.
@ r3 = number of characters to search in alignment loop
and r3, r0, #7
uxtb r1, r1
rsb r3, r3, #15 @ 16 - 1 peeled loop iteration
cmp r2, r1
it eq
bxeq lr
@ Loop until we find ...
1: ldrb r2, [r0, #1]!
subs r3, r3, #1 @ ... the alignment point
it ne
cmpne r2, r1 @ ... or C
bne 1b
@ Disambiguate the exit possibilites above
cmp r2, r1 @ Found C
it eq
bxeq lr
add r0, r0, #1
@ So now we're aligned.
ldrd r2, r3, [r0], #8
orr r1, r1, r1, lsl #8 @ Replicate C to all bytes
#ifdef ARCH_HAS_T2
movw ip, #0x0101
pld [r0, #64]
movt ip, #0x0101
#else
ldr ip, =0x01010101
pld [r0, #64]
#endif
orr r1, r1, r1, lsl #16
@ Loop searching for C, 8 bytes at a time.
@ Subtracting (unsigned saturating) from 1 means result of 1 for
@ any byte that was originally zero and 0 otherwise. Therefore
@ we consider the lsb of each byte the "found" bit.
2: eor r2, r2, r1 @ Convert C bytes to 0
eor r3, r3, r1
uqsub8 r2, ip, r2 @ Find C
uqsub8 r3, ip, r3
pld [r0, #128]
orrs r3, r3, r2 @ Test both words for found
it eq
ldrdeq r2, r3, [r0], #8
beq 2b
@ Found something. Disambiguate between first and second words.
@ Adjust r0 to point to the word containing the match.
@ Adjust r2 to the found bits for the word containing the match.
cmp r2, #0
sub r0, r0, #4
ite eq
moveq r2, r3
subne r0, r0, #4
@ Find the bit-offset of the match within the word. Note that the
@ bit result from clz will be 7 higher than "true", but we'll
@ immediately discard those bits converting to a byte offset.
#ifdef __ARMEL__
rev r2, r2 @ For LE, count from the little end
#endif
clz r2, r2
add r0, r0, r2, lsr #3 @ Adjust the pointer to the found byte
bx lr
END (__rawmemchr)
weak_alias (__rawmemchr, rawmemchr)
libc_hidden_def (__rawmemchr)
|
