/* strlen -- find the length of a nul-terminated string. Copyright (C) 2013-2024 Free Software Foundation, Inc. This file is part of the GNU C Library. The GNU C Library is free software; you can redistribute it and/or modify it under the terms of the GNU Lesser General Public License as published by the Free Software Foundation; either version 2.1 of the License, or (at your option) any later version. The GNU C Library is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General Public License for more details. You should have received a copy of the GNU Lesser General Public License along with the GNU C Library. If not, see . */ #include .syntax unified .text ENTRY (strlen) @ r0 = start of string ldrb r2, [r0] @ load the first byte asap @ To cater to long strings, we want to search through a few @ characters until we reach an aligned pointer. To cater to @ small strings, we don't want to start doing word operations @ immediately. The compromise is a maximum of 16 bytes less @ whatever is required to end with an aligned pointer. @ r3 = number of characters to search in alignment loop and r3, r0, #7 mov r1, r0 @ Save the input pointer rsb r3, r3, #15 @ 16 - 1 peeled loop iteration cmp r2, #0 beq 99f @ Loop until we find ... 1: ldrb r2, [r0, #1]! subs r3, r3, #1 @ ... the alignment point it ne cmpne r2, #0 @ ... or EOS bne 1b @ Disambiguate the exit possibilities above cmp r2, #0 @ Found EOS beq 99f add r0, r0, #1 @ So now we're aligned. ldrd r2, r3, [r0], #8 #ifdef ARCH_HAS_T2 movw ip, #0x0101 pld [r0, #64] movt ip, #0x0101 #else ldr ip, =0x01010101 pld [r0, #64] #endif @ Loop searching for EOS, 8 bytes at a time. @ Subtracting (unsigned saturating) from 1 for any byte means that @ we get 1 for any byte that was originally zero and 0 otherwise. @ Therefore we consider the lsb of each byte the "found" bit. .balign 16 2: uqsub8 r2, ip, r2 @ Find EOS uqsub8 r3, ip, r3 pld [r0, #128] @ Prefetch 2 lines ahead orrs r3, r3, r2 @ Combine the two words it eq ldrdeq r2, r3, [r0], #8 beq 2b @ Found something. Disambiguate between first and second words. @ Adjust r0 to point to the word containing the match. @ Adjust r2 to the found bits for the word containing the match. cmp r2, #0 sub r0, r0, #4 ite eq moveq r2, r3 subne r0, r0, #4 @ Find the bit-offset of the match within the word. Note that the @ bit result from clz will be 7 higher than "true", but we'll @ immediately discard those bits converting to a byte offset. #ifdef __ARMEL__ rev r2, r2 @ For LE, count from the little end #endif clz r2, r2 add r0, r0, r2, lsr #3 @ Adjust the pointer to the found byte 99: sub r0, r0, r1 @ Subtract input to compute length bx lr END (strlen) libc_hidden_builtin_def (strlen)