From a334319f6530564d22e775935d9c91663623a1b4 Mon Sep 17 00:00:00 2001 From: Ulrich Drepper Date: Wed, 22 Dec 2004 20:10:10 +0000 Subject: (CFLAGS-tst-align.c): Add -mpreferred-stack-boundary=4. --- stdlib/ldiv.c | 54 ------------------------------------------------------ 1 file changed, 54 deletions(-) delete mode 100644 stdlib/ldiv.c (limited to 'stdlib/ldiv.c') diff --git a/stdlib/ldiv.c b/stdlib/ldiv.c deleted file mode 100644 index a7796d8e95..0000000000 --- a/stdlib/ldiv.c +++ /dev/null @@ -1,54 +0,0 @@ -/* Copyright (C) 1992, 1997 Free Software Foundation, Inc. - This file is part of the GNU C Library. - - The GNU C Library is free software; you can redistribute it and/or - modify it under the terms of the GNU Lesser General Public - License as published by the Free Software Foundation; either - version 2.1 of the License, or (at your option) any later version. - - The GNU C Library is distributed in the hope that it will be useful, - but WITHOUT ANY WARRANTY; without even the implied warranty of - MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU - Lesser General Public License for more details. - - You should have received a copy of the GNU Lesser General Public - License along with the GNU C Library; if not, write to the Free - Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA - 02111-1307 USA. */ - -#include - - -/* Return the `ldiv_t' representation of NUMER over DENOM. */ -ldiv_t -ldiv (long int numer, long int denom) -{ - ldiv_t result; - - result.quot = numer / denom; - result.rem = numer % denom; - - /* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where - NUMER / DENOM is to be computed in infinite precision. In - other words, we should always truncate the quotient towards - zero, never -infinity. Machine division and remainer may - work either way when one or both of NUMER or DENOM is - negative. If only one is negative and QUOT has been - truncated towards -infinity, REM will have the same sign as - DENOM and the opposite sign of NUMER; if both are negative - and QUOT has been truncated towards -infinity, REM will be - positive (will have the opposite sign of NUMER). These are - considered `wrong'. If both are NUM and DENOM are positive, - RESULT will always be positive. This all boils down to: if - NUMER >= 0, but REM < 0, we got the wrong answer. In that - case, to get the right answer, add 1 to QUOT and subtract - DENOM from REM. */ - - if (numer >= 0 && result.rem < 0) - { - ++result.quot; - result.rem -= denom; - } - - return result; -} -- cgit 1.4.1