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-/* Optimized strlen implementation for PowerPC.
-   Copyright (C) 1997-2017 Free Software Foundation, Inc.
-   This file is part of the GNU C Library.
-
-   The GNU C Library is free software; you can redistribute it and/or
-   modify it under the terms of the GNU Lesser General Public
-   License as published by the Free Software Foundation; either
-   version 2.1 of the License, or (at your option) any later version.
-
-   The GNU C Library is distributed in the hope that it will be useful,
-   but WITHOUT ANY WARRANTY; without even the implied warranty of
-   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
-   Lesser General Public License for more details.
-
-   You should have received a copy of the GNU Lesser General Public
-   License along with the GNU C Library; if not, see
-   <http://www.gnu.org/licenses/>.  */
-
-#include <sysdep.h>
-
-/* The algorithm here uses the following techniques:
-
-   1) Given a word 'x', we can test to see if it contains any 0 bytes
-      by subtracting 0x01010101, and seeing if any of the high bits of each
-      byte changed from 0 to 1. This works because the least significant
-      0 byte must have had no incoming carry (otherwise it's not the least
-      significant), so it is 0x00 - 0x01 == 0xff. For all other
-      byte values, either they have the high bit set initially, or when
-      1 is subtracted you get a value in the range 0x00-0x7f, none of which
-      have their high bit set. The expression here is
-      (x + 0xfefefeff) & ~(x | 0x7f7f7f7f), which gives 0x00000000 when
-      there were no 0x00 bytes in the word.  You get 0x80 in bytes that
-      match, but possibly false 0x80 matches in the next more significant
-      byte to a true match due to carries.  For little-endian this is
-      of no consequence since the least significant match is the one
-      we're interested in, but big-endian needs method 2 to find which
-      byte matches.
-
-   2) Given a word 'x', we can test to see _which_ byte was zero by
-      calculating ~(((x & 0x7f7f7f7f) + 0x7f7f7f7f) | x | 0x7f7f7f7f).
-      This produces 0x80 in each byte that was zero, and 0x00 in all
-      the other bytes. The '| 0x7f7f7f7f' clears the low 7 bits in each
-      byte, and the '| x' part ensures that bytes with the high bit set
-      produce 0x00. The addition will carry into the high bit of each byte
-      iff that byte had one of its low 7 bits set. We can then just see
-      which was the most significant bit set and divide by 8 to find how
-      many to add to the index.
-      This is from the book 'The PowerPC Compiler Writer's Guide',
-      by Steve Hoxey, Faraydon Karim, Bill Hay and Hank Warren.
-
-   We deal with strings not aligned to a word boundary by taking the
-   first word and ensuring that bytes not part of the string
-   are treated as nonzero. To allow for memory latency, we unroll the
-   loop a few times, being careful to ensure that we do not read ahead
-   across cache line boundaries.
-
-   Questions to answer:
-   1) How long are strings passed to strlen? If they're often really long,
-   we should probably use cache management instructions and/or unroll the
-   loop more. If they're often quite short, it might be better to use
-   fact (2) in the inner loop than have to recalculate it.
-   2) How popular are bytes with the high bit set? If they are very rare,
-   on some processors it might be useful to use the simpler expression
-   ~((x - 0x01010101) | 0x7f7f7f7f) (that is, on processors with only one
-   ALU), but this fails when any character has its high bit set.  */
-
-/* Some notes on register usage: Under the SVR4 ABI, we can use registers
-   0 and 3 through 12 (so long as we don't call any procedures) without
-   saving them. We can also use registers 14 through 31 if we save them.
-   We can't use r1 (it's the stack pointer), r2 nor r13 because the user
-   program may expect them to hold their usual value if we get sent
-   a signal. Integer parameters are passed in r3 through r10.
-   We can use condition registers cr0, cr1, cr5, cr6, and cr7 without saving
-   them, the others we must save.  */
-
-/* int [r3] strlen (char *s [r3])  */
-
-ENTRY (strlen)
-
-#define rTMP4	r0
-#define rRTN	r3	/* incoming STR arg, outgoing result */
-#define rSTR	r4	/* current string position */
-#define rPADN	r5	/* number of padding bits we prepend to the
-			   string to make it start at a word boundary */
-#define rFEFE	r6	/* constant 0xfefefeff (-0x01010101) */
-#define r7F7F	r7	/* constant 0x7f7f7f7f */
-#define rWORD1	r8	/* current string word */
-#define rWORD2	r9	/* next string word */
-#define rMASK	r9	/* mask for first string word */
-#define rTMP1	r10
-#define rTMP2	r11
-#define rTMP3	r12
-
-
-	clrrwi	rSTR, rRTN, 2
-	lis	r7F7F, 0x7f7f
-	rlwinm	rPADN, rRTN, 3, 27, 28
-	lwz	rWORD1, 0(rSTR)
-	li	rMASK, -1
-	addi	r7F7F, r7F7F, 0x7f7f
-/* We use method (2) on the first two words, because rFEFE isn't
-   required which reduces setup overhead.  Also gives a faster return
-   for small strings on big-endian due to needing to recalculate with
-   method (2) anyway.  */
-#ifdef __LITTLE_ENDIAN__
-	slw	rMASK, rMASK, rPADN
-#else
-	srw	rMASK, rMASK, rPADN
-#endif
-	and	rTMP1, r7F7F, rWORD1
-	or	rTMP2, r7F7F, rWORD1
-	add	rTMP1, rTMP1, r7F7F
-	nor	rTMP3, rTMP2, rTMP1
-	and.	rTMP3, rTMP3, rMASK
-	mtcrf	0x01, rRTN
-	bne	L(done0)
-	lis	rFEFE, -0x101
-	addi	rFEFE, rFEFE, -0x101
-/* Are we now aligned to a doubleword boundary?  */
-	bt	29, L(loop)
-
-/* Handle second word of pair.  */
-/* Perhaps use method (1) here for little-endian, saving one instruction?  */
-	lwzu	rWORD1, 4(rSTR)
-	and	rTMP1, r7F7F, rWORD1
-	or	rTMP2, r7F7F, rWORD1
-	add	rTMP1, rTMP1, r7F7F
-	nor.	rTMP3, rTMP2, rTMP1
-	bne	L(done0)
-
-/* The loop.  */
-
-L(loop):
-	lwz	rWORD1, 4(rSTR)
-	lwzu	rWORD2, 8(rSTR)
-	add	rTMP1, rFEFE, rWORD1
-	nor	rTMP2, r7F7F, rWORD1
-	and.	rTMP1, rTMP1, rTMP2
-	add	rTMP3, rFEFE, rWORD2
-	nor	rTMP4, r7F7F, rWORD2
-	bne	L(done1)
-	and.	rTMP3, rTMP3, rTMP4
-	beq	L(loop)
-
-#ifndef __LITTLE_ENDIAN__
-	and	rTMP1, r7F7F, rWORD2
-	add	rTMP1, rTMP1, r7F7F
-	andc	rTMP3, rTMP4, rTMP1
-	b	L(done0)
-
-L(done1):
-	and	rTMP1, r7F7F, rWORD1
-	subi	rSTR, rSTR, 4
-	add	rTMP1, rTMP1, r7F7F
-	andc	rTMP3, rTMP2, rTMP1
-
-/* When we get to here, rSTR points to the first word in the string that
-   contains a zero byte, and rTMP3 has 0x80 for bytes that are zero,
-   and 0x00 otherwise.  */
-L(done0):
-	cntlzw	rTMP3, rTMP3
-	subf	rTMP1, rRTN, rSTR
-	srwi	rTMP3, rTMP3, 3
-	add	rRTN, rTMP1, rTMP3
-	blr
-#else
-
-L(done0):
-	addi	rTMP1, rTMP3, -1	/* Form a mask from trailing zeros.  */
-	andc	rTMP1, rTMP1, rTMP3
-	cntlzw	rTMP1, rTMP1		/* Count bits not in the mask.  */
-	subf	rTMP3, rRTN, rSTR
-	subfic	rTMP1, rTMP1, 32-7
-	srwi	rTMP1, rTMP1, 3
-	add	rRTN, rTMP1, rTMP3
-	blr
-
-L(done1):
-	addi	rTMP3, rTMP1, -1
-	andc	rTMP3, rTMP3, rTMP1
-	cntlzw	rTMP3, rTMP3
-	subf	rTMP1, rRTN, rSTR
-	subfic	rTMP3, rTMP3, 32-7-32
-	srawi	rTMP3, rTMP3, 3
-	add	rRTN, rTMP1, rTMP3
-	blr
-#endif
-
-END (strlen)
-libc_hidden_builtin_def (strlen)