BZ #13792: License manual example source files under GPL.

1 files changed, 24 insertions, 7 deletions

diff --git a/manual/examples/genpass.c b/manual/examples/genpass.c
index a7626dbed5..cb4d99f069 100644
--- a/manual/examples/genpass.c
+++ b/manual/examples/genpass.c
@@ -1,31 +1,48 @@
+/* Encrypting Passwords
+   Copyright (C) 1991-2012 Free Software Foundation, Inc.
+
+   This program is free software; you can redistribute it and/or
+   modify it under the terms of the GNU General Public License
+   as published by the Free Software Foundation; either version 2
+   of the License, or (at your option) any later version.
+
+   This program is distributed in the hope that it will be useful,
+   but WITHOUT ANY WARRANTY; without even the implied warranty of
+   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+   GNU General Public License for more details.
+
+   You should have received a copy of the GNU General Public License
+   along with this program; if not, if not, see <http://www.gnu.org/licenses/>.
+*/
+
 #include <stdio.h>
 #include <time.h>
 #include <unistd.h>
 #include <crypt.h>
 
-int 
+int
 main(void)
 {
   unsigned long seed[2];
   char salt[] = "$1$........";
-  const char *const seedchars = 
+  const char *const seedchars =
     "./0123456789ABCDEFGHIJKLMNOPQRST"
     "UVWXYZabcdefghijklmnopqrstuvwxyz";
   char *password;
   int i;
-  
-  /* Generate a (not very) random seed.  
+
+  /* Generate a (not very) random seed.
      You should do it better than this...  */
   seed[0] = time(NULL);
   seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
-  
+
   /* Turn it into printable characters from `seedchars'.  */
   for (i = 0; i < 8; i++)
     salt[3+i] = seedchars[(seed[i/5] >> (i%5)*6) & 0x3f];
-  
+
   /* Read in the user's password and encrypt it.  */
   password = crypt(getpass("Password:"), salt);
-  
+
   /* Print the results.  */
   puts(password);
   return 0;